56 lines
1.2 KiB
C
56 lines
1.2 KiB
C
// Let list1 = (x1, x2…..xn) and list2= (y1, y2…..ym). Write a function to merge list1 and
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// list2 to obtain list3 = (x1, y1, x2, y2….xm,ym,xm+1…xn) for m<=n; and list3=(x1,
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// y1,x2,y2…..xn, yn, xn+1….xm) for m>n.
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#include <stdio.h>
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#include <stdlib.h>
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#define MAX_SIZE 100
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void merge_lists(int list1[], int n, int list2[], int m, int list3[]) {
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int i = 0, j = 0, k = 0;
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while (i < n && j < m) {
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list3[k++] = list1[i++];
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list3[k++] = list2[j++];
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}
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while (i < n) {
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list3[k++] = list1[i++];
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}
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while (j < m) {
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list3[k++] = list2[j++];
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}
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}
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int main() {
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int list1[MAX_SIZE], list2[MAX_SIZE], list3[MAX_SIZE * 2];
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int n, m, i;
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printf("Enter the number of elements in list1: ");
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scanf("%d", &n);
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printf("Enter the elements of list1:\n");
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for (i = 0; i < n; i++) {
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scanf("%d", &list1[i]);
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}
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printf("Enter the number of elements in list2: ");
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scanf("%d", &m);
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printf("Enter the elements of list2:\n");
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for (i = 0; i < m; i++) {
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scanf("%d", &list2[i]);
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}
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merge_lists(list1, n, list2, m, list3);
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printf("Merged list:\n");
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for (i = 0; i < n + m; i++) {
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printf("%d ", list3[i]);
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}
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printf("\n");
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return 0;
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}
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